Re^3: Is it possible to store an arthimetric operator in a variable?

[Adam]

You are correct that the code isn't using the prototypes or requires the 1:0. I used them both, however, to be very clear to our anonymous reader what it was the code was doing. Also, I used 1:0 because I don't like using undef as a boolean false; it's not relevant here, but I find that 0 as false makes debugging easier which has led to this habit.

[ikegami]

Boolean false isn't undef. Notice the lack of warnings in the following snippet:

>perl -we "print(1==2)"

>

[Adam]

Sorry, you are right. It's "", which is just as useless in debugging... (it's been so long that I wrote a boolean function where I didn't use 0 that I forgot. Thank you.)

[benizi]

Actually, it's the special variable !1, which stringifies to "", but has the numeric value of 0.

See: Re^4: m//g behaves strange... (!1)