Merging hashes

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RE: Merging hashes by Anonymous Monk on Dec 30, 1999 at 10:13 UTC
how about just this: %foo = (%foo, %bar); the "(" cats the hashes in array context, making one long array with an even number of elements, then assigns that to a hash. Of course this is memory intensive for large hashes. So this is really not very good after all. I must meditate some more in silence...	[reply]
RE: Merging hashes by Anonymous Monk on Jan 02, 2000 at 20:34 UTC
Perl is very wise. I have not tested, but I assume that in the case of %foo = (%foo, %bar); that the values of %bar that share keys with %foo will over write the value in the cat and the value in the new %foo will be from %bar? Sorry that sentence was so long, I got caught up in the moment. I use this, not only to garuntee %bar will over write %foo, but so anyone who looks at the code after me will have no dougts as to what I was attempting: `foreach my $key (keys(%bar)){ $foo{$key} = $bar{$key}; }` [download] It is iterative, but shouldn't consume too much memory. This will even pass pointers kept in values. I'm afraid a cat would expand the array I was pointing to aswell. I have never tried though. -T	[reply] [d/l]
RE: Merging hashes by root (Monk) on Oct 13, 1999 at 04:05 UTC
I liked this meditation.	[reply]
RE: Merging hashes by Anonymous Monk on Apr 07, 2000 at 08:40 UTC
Este es... the usual mesh.	[reply]
Re: Merging hashes by Anonymous Monk on Oct 05, 2013 at 16:30 UTC
What about something deeper? A deeper meditation? For example a hash containing hashes where the second hash, %bar, takes presidence	[reply]
Re^2: Merging hashes by Anonymous Monk on Oct 05, 2013 at 17:12 UTC
What about it?	[reply]


Think about Loose Coupling
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