Re^3: One out of three ain't bad (order)

[mrborisguy]

Which seems to work right now, since you've seen the progression of what came before. But in 2 months, I can imagine you thinking, "Now why in the world is there a two in there... I must want two of them to be true" on your first look while skimming your code.

    -Bryan

[Dr. Mu]

True enough. I suppose what's lacking is a commonly-accepted idiom for Boolean conversions. We have 0+ for numeric conversions; so perhaps !! wasn't so bad after all, even though two operations are implied (unless the compiler optimizes them out). 0|| and 1&& would also work.

[tye]

No, 0||$x is just $x, not "Booleanized" $x. perl -le"print 0||5" prints 5 not 1 and perl -le"print 1&&@ARGV" x y z prints xyz.

[Dr. Mu]

So, once again in Perl,

$conjecture->obviously_so == 1 && $conjecture->true == 0

Thanks, tye, for testing something I should've! (tho' the logic of Boolean diadics not returning Boolean values escapes me...)