Re: need regular expression

by tilly (Archbishop)

on Nov 02, 2005 at 08:08 UTC ( #504861=note: print w/replies, xml )

Need Help??

Untested. s/(\d?\d)(-\d?\d-\d?\d)/(2000+$1).$2/eg

Comment on Re: need regular expression Download Code

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Re^2: need regular expression by Corion (Pope) on Nov 02, 2005 at 08:12 UTC
That one won't promote single-digit numbers to double-digit numbers. `s/(\d?\d)(-\d?\d)-(\d?\d)/(2000+$1).sprintf("%02g", $2).sprintf("%02g" +,$3)/eg` [download] could do it, but that's similarly untested :-)	[reply] [d/l]
Re^3: need regular expression by tilly (Archbishop) on Nov 02, 2005 at 08:17 UTC
The listed examples didn't indicate to me that we need to worry about anything other than the first number, and adding 2000 to a 1 digit number definitely results in a 4 digit one. :-) But if that's your spec, then try `s/(\d?\d)-(\d?\d)-(\d?\d)/sprintf("20%02d-%02d-%02d", $1, $2, $3)/eg`	[reply] [d/l]

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