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Re^2: AES Interoperability between Perl and C#by ikegami (Patriarch) |
| on Nov 16, 2005 at 19:33 UTC ( [id://509249]=note: print w/replies, xml ) | Need Help?? |
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There! Figured it out! There is an IV in Crypt::Rijndael and there is a different one in Crypt::CBC. Previously, I thought there was a conflict between the two. However, I finally realized the one in Crypt::Rijndael is not used when Crypt::Rijndael is used through Crypt::CBC. Crypt::CBC uses Crypt::Rijndael in ECB mode. In ECB mode, Crypt::Rijndael doesn't use its IV, leaving Crypt::CBC free to use its IV. So why must the Crypt::CBC IV be 8 bytes long? It turns out that Crypt::CBC works with 16 byte blocks with Crypt::Rijndael, so the IV must be 16 bytes long for Crypt::CBC too! It turns out the IV length check is bogus. So all you need to do is to bypass the IV length check. It's actually quite simple: Use the method iv instead of the method get_initialization_vector and set_initialization_vector, or use the iv argument to the Crypt::CBC constructor. These don't check the length of the supplied IV. For example: or
(Untested. I don't have these modules.)
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