in reply to Re: AES Interoperability between Perl and C#
in thread AES Interoperability between Perl and C#
There! Figured it out!
There is an IV in Crypt::Rijndael and there is a different one in Crypt::CBC. Previously, I thought there was a conflict between the two. However, I finally realized the one in Crypt::Rijndael is not used when Crypt::Rijndael is used through Crypt::CBC. Crypt::CBC uses Crypt::Rijndael in ECB mode. In ECB mode, Crypt::Rijndael doesn't use its IV, leaving Crypt::CBC free to use its IV.
So why must the Crypt::CBC IV be 8 bytes long? It turns out that Crypt::CBC works with 16 byte blocks with Crypt::Rijndael, so the IV must be 16 bytes long for Crypt::CBC too! It turns out the IV length check is bogus.
So all you need to do is to bypass the IV length check. It's actually quite simple: Use the method iv instead of the method get_initialization_vector and set_initialization_vector, or use the iv argument to the Crypt::CBC constructor. These don't check the length of the supplied IV. For example:
oruse Crypt::CBC; $cipher = Crypt::CBC->new( -cipher => 'Rijndael', ... ); $cipher->iv($iv); $ciphertext = $cipher->encrypt("This data is hush hush"); $plaintext = $cipher->decrypt($ciphertext);
use Crypt::CBC; $cipher = Crypt::CBC->new( -cipher => 'Rijndael', -iv => $iv, ... ); $ciphertext = $cipher->encrypt("This data is hush hush"); $plaintext = $cipher->decrypt($ciphertext);
(Untested. I don't have these modules.)
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Re^3: AES Interoperability between Perl and C#
by jpfarmer (Pilgrim) on Nov 17, 2005 at 20:12 UTC |