Re: Perl Idioms Explained - my $count = () = /.../g

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a list assignment in scalar context returns the number of elements on the right-hand side of the list assignment

I don't agree with that. An array assignment does this. A list assignment returns the last element. To wit:

@A = (1,3,5);
$scalar_array  = @A;
$scalar_list   = (1,3,5);
$scalar_weird  = (1..5);

print "SA: ", $scalar_array, $/;
print "SL: ", $scalar_list, $/;
print "SW: ", $scalar_weird, $/;
=for shell
  metaperl@pool-71-109-151-76:~/tmp$ perl a.pl
SA: 3
SL: 5
SW: 
=cut
[download]

Comment on Re: Perl Idioms Explained - my $count = () = /.../g Download Code

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Re^2: Perl Idioms Explained - my $count = () = /.../g by japhy (Canon) on Feb 05, 2006 at 16:23 UTC
You misunderstood me. A list assignment in scalar context returns the number of elements. my $count = (LIST1) = (LIST2); The chunk in bold is the list assignment. That is put in scalar context by the `my $count = ...` part. Please see Re: Longest repeated string... for further clarification. Jeff `japhy` Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and `perl` hacker How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart	[reply] [d/l]
Re^2: Perl Idioms Explained - my $count = () = /.../g by MrCricket (Sexton) on Dec 17, 2015 at 10:18 UTC
About the `$scalar_weird = (1..5); print "SW: ", $scalar_weird, $/; SW:` [download] -it's not a 'range' operator but a 'flip-flop', returns false in your case, http://perlhacks.com/2014/01/dots-perl/	[reply] [d/l]

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