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printf vs. sprintf

by henrylaxen (Novice)
on Jan 25, 2001 at 06:25 UTC ( [id://54187] : CUFP . print w/replies, xml ) Need Help??

This one bit me today, and seemed quite mysterious for awhile:
@a = ('a%sc','b'); printf @a; # prints abc print sprintf @a; # prints 2

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Re (tilly) 1: printf vs. sprintf
by tilly (Archbishop) on Jan 25, 2001 at 08:46 UTC
    It seemed mysterious only for a while? I am impressed!

    Those who are curious about how you too can induce needless confusion in hapless fools who want to use your code can read FMTYEWTK About Prototypes... (No, this is not one of the corners of the Perl language that I think was a particularly good idea...)

Re: printf vs. sprintf
by petral (Curate) on Jan 25, 2001 at 21:04 UTC
      @a = ('a%sc','b'); printf @a; # prints abc print "\n"; printf scalar @a; # prints 2 print "\n"; print sprintf @a; # prints 2 print "\n"; print sprintf @a[0,1]; # prints b print "\n"; print @a[0,1]; # prints a%scb print "\n"; print scalar @a[0,1]; # prints b print "\n"; print $a[1]; # prints b print "\n"; $huh = scalar @a[0,1]; # prints huhb print "huh", $huh; print "\n"; printf sprintf @a[0,1]; # prints b
      so sprintf evals in scalar (?) context, printf in array? Is there a why behind this?


        The explanation I remember from perl5-porters for this odd difference in behavior involves the optional filehandle argument for printf. The way prototypes were designed for the builtin functions, a prototype which allows for an indirect object has to specify list context for all the regular arguments. Since sprintf doesn't have an optional file handle argument, its prototype specifies a scalar for the first argument, and a list for the remaining arguments.

        So, this difference in behavior between printf and sprintf is more by accident than by design. While the prototype for sprintf could be changed to match the prototype for printf, doing so would break backwards compatibility, particularly where the first argument to sprintf is a subroutine call.