http://www.perlmonks.org?node_id=562251


in reply to Re^2: tie'ing a scalar as an array?
in thread tie'ing a scalar as an array?

Ok, Here goes a more complex example, wich shows it in more details:

use strict; use warnings; package Foo::Bar; sub new { tie my @arr, 'Foo::Bar'; return bless \@arr, 'Foo::Bar'; } sub TIEARRAY { my $scalar = "A Scalar"; return bless \$scalar, 'Foo::Bar'; } sub FETCH { my ($self, $index) = @_; print 'FETCH '; if ($index == 0) { return $self->lalala0; } elsif ($index == 1) { return $self->lalala1; } else { return undef; } } sub STORE { my ($self, $index, $value) = @_; print 'STORE '; if ($index == 0) { return $self->lalala0($value); } elsif ($index == 1) { return $self->lalala1($value); } else { return undef; } } sub lalala { my $self = shift; if (UNIVERSAL::isa($self,'ARRAY')) { $self = tied(@{$self}) }; print "Lalala $self\n"; } sub lalala0 { my $self = shift; if (UNIVERSAL::isa($self,'ARRAY')) { $self = tied(@{$self}) }; print "Lalala0 $self\n"; } sub lalala1 { my $self = shift; if (UNIVERSAL::isa($self,'ARRAY')) { $self = tied(@{$self}) }; print "Lalala1 $self\n"; } sub DESTROY { my $self = shift; if (UNIVERSAL::isa($self,'ARRAY')) { print "Destroying the array...\n"; } else { print "Destroying the scalar...\n"; } } package main; my $a = Foo::Bar->new(); # The object inside is a SCALAR $a->lalala(); $a->[0] = $a->[1]; $a->[1] = $a->[0];

UPDATE: Included the DESTROY method, to illustrate...

daniel