in reply to Re^3: Secret Perl Operators: the boolean list squash operator, x!!
in thread Secret Perl Operators: the boolean list squash operator, x!!
I see. Actually to prevent confusion ... even this would autovivify:
I guess we'd need to "fix" the x operator to not evaluate the lefthand operator if the righthand one is <=0.@a = ( $hash{foo}{bar} x!! 0);
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