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Re^3: Permutation of groups

by tomazos (Deacon)
on Nov 20, 2006 at 20:16 UTC ( [id://585133]=note: print w/replies, xml ) Need Help??


in reply to Re^2: Permutation of groups
in thread Permutation of groups

Specifically for a given partitioning ever person must belong to exactly one team.

Teams do not have to be of the same size.

eg For three people: 1. A B C 2. AB C 3. A BC 4. AC B 5. ABC

Replies are listed 'Best First'.
Re^4: Permutation of groups
by Limbic~Region (Chancellor) on Nov 20, 2006 at 20:50 UTC
    tomazos,
    Assuming it does the right thing, you are going to want to use the integer partitioning code blokhead refers to above and the binary counting I explained. You will not have a contigous range of team reference numbers but they will be guaranteed to be unique and will never be higher than 2 ** $num_of_people.

    If I find the time tonight or tomorrow, I will code this for you. If you end up coding it on your own, please post so others can benefit and I won't bother.

    Cheers - L~R

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