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### Re^2: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)

 on Sep 11, 2007 at 23:40 UTC ( #638460=note: print w/replies, xml ) Need Help??

Another solution, much more verbose but certainly more readable:

```#!/usr/bin/env python

str = "ABBBCCDDZ"

parts = []
last_char = ''
current_chunk = ''
for i in range(len(str)):
current_char = str[i]
if (current_chunk == '') or (last_char == current_char):
current_chunk = current_chunk + current_char
else:
parts.append(current_chunk)
current_chunk = current_char
last_char = current_char
if len(current_chunk)>0:
parts.append(current_chunk)
print parts

Also available here:

http://pastebin.com/f1213db97

- Antonio Ognio, Lima-Peru

• Comment on Re^2: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)

Replies are listed 'Best First'.
Re^3: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)
by erroneousBollock (Curate) on Sep 12, 2007 at 10:08 UTC
I find them equivalently unreadable ;-)
Re^3: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)
by MonkOfAnotherSect (Sexton) on Sep 13, 2007 at 04:32 UTC
Gnah. No No and No.

The itertools version is quite lovely, but if you must do an iterative version please at least make it idiomatic. If you really needed an index, you could at least use enumerate() ;-P

```mystr = "ABBBCCDDZ"

def get_iterparts(mystr):
buf = ""
for char in mystr:
if not buf or buf.endswith(char):
buf += char
else:
yield buf
buf = char
if buf:
yield buf
print list(get_iterparts(mystr))

def get_parts(mystr):
parts = []
buf = ""
for char in mystr:
if not buf or buf.endswith(char):
buf += char
else:
parts.append(buf)
buf = char
if buf:
parts.append(buf)
return parts
print get_parts(mystr)

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