Re: Re: Regular Expression Question

[larryk]

you are right to suspect that this would not work - the single \d as opposed to \d+ before the % would mean that the regex would fail to match unless the % was between 0 and 9.

what I expect you are looking for is for(<>) { /(\d+)%/; print if $1 >= 88 }

[SilverB1rd]

Thanks larry. Typo on my part. It was supposed to be (\d+)%

------
The Price of Freedom is Eternal Vigilance