### Re: Re: sort mechanism

by extremely (Priest)
 on Apr 06, 2001 at 23:17 UTC ( #70563=note: print w/replies, xml ) Need Help??

in reply to Re: sort mechanism

No that doesn't work. The parens basically are no-ops there. a scalar is just a scalar. You would need @{\$a} to explode the array.

update (GOOD band names =)

--
\$you = new YOU;
honk() if \$you->love(perl)

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Re: Re: Re: sort mechanism
by McD (Chaplain) on Apr 06, 2001 at 23:32 UTC
Um... right. I don't think I was completely clear - what I was trying to point out was that <=> has different behavior when comparing lists than when comparing scalars.

Although comparing two lists of a single scalar each is, as you said, exactly like comparing the naked scalars.

So what have we learned?

1. I shouldn't node before coffee, no matter what the hour.
2. "Naked Scalars" would be a pretty good name for a rock and roll band.
3. So would "Spaceship Operator."
4. I still can't find where <=>'s behavior in list context is documented.
Peace,
-McD
The equality operators apply scalar context to both sides. Try this out and see. Operators apply context. I don't think they often respond to it but with perl anything is possible =)
```my @a = keys %env;
my @b = values %env;
my @c = ( "equal", "a > b", "b > a" );
print (\$c[@a<=>@b]),\$/;

No really, damn good band names... =)

--
\$you = new YOU;
honk() if \$you->love(perl)

Ok, then riddle me this:

```#!/usr/local/bin/perl -l

my @a = (1, 2, 3);
my @b = (1, 2, 4);
my @c = ( "equal", "a > b", "b > a" );

print (\$c[@a<=>@b]);
print (\$c[@b<=>@a]);
print (\$c[(1, 2, 3)<=>(1, 2, 4)]);
print (\$c[(1, 2, 4)<=>(1, 2, 3)]);

Produces:

```equal
equal
b > a
a > b
```
Something about the difference between an array and a list, I suspect - a distinction oft unclear in my mind, regardless of caffine levels.

Peace,
-McD

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