Re: extract file name from a dynamic path

[ikegami]

Use File::Basename's basename. It's part of Perl.

[alexm]

While writing my last CUFP I found a warning about basename in File::Basename:

This function is provided for compatibility with the Unix shell command basename(1). It does NOT always return the file name portion of a path as you might expect. To be safe, if you want the file name portion of a path use fileparse().

I'd like to see an example of this, since I can't figure out what can be wrong with basename.

[Anonymous Monk]

Just keep reading, it says

C<basename()> returns the last level of a filepath even if the last
level is clearly directory.  In effect, it is acting like C<pop()> for
paths.  This differs from C<fileparse()>'s behaviour.

    # Both return "bar"
    basename("/foo/bar");
    basename("/foo/bar/");

[alexm]

I was blind when I read that, thanks :)