Re: trouble taking reference of function

[samtregar]

Perl's builtins aren't generally made available as subs you can take a reference to. This works though:

  my $foo = sub { sin(@_) };
  print $foo->(0.5), "\n";

-sam

[ikegami]

Beware of prototypes when dealing with functions and named operators.

$ perl -wle'print sin(0.5) == sub { sin(@_)    }->(0.5) ?1:0'
0

$ perl -wle'print sin(0.5) == sub { sin($_[0]) }->(0.5) ?1:0'
1

Update: Added code.

[Lawliet]

Huh? Why does that happen?

[kyle]

The argument to sin is in scalar context (it has a prototype of "_").