Re^3: partition of an array


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Re^3: partition of an array

by f00li5h (Chaplain)

on Mar 25, 2009 at 06:44 UTC ( [id://753032]=note: print w/replies, xml )

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in reply to Re^2: partition of an array
in thread partition of an array

Does not.

Output:

$VAR1 = [ '1', '1', '2', '2' ]; $VAR2 = [ '1', '2', '2', '4' ];
we have 6 and 9
[download]

You dropped the sort bit!

... some time passes ...

Just snagging the biggest one and stuffing it in a sack works pretty well for the knapsack problem... and since this one was only 2 partitions it didn't do too bad ;)

@_=qw; ask f00li5h to appear and remain for a moment of pretend better than a lifetime;;s;;@_[map hex,split'',B204316D8C2A4516DE];;y/05/os/&print;

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