Re: num keys of the hash within hash?

[muzakfetch]

Maybe this is what you're looking for:

#!/usr/bin/perl

use warnings;
use strict;

my $hashref = {
   first => {
       foo => bar,
       bar => baz,
       flop => floodle
   },
   second => {
       bar => foo,
       baz => bar,
       etc  => plodle
   }
};

foreach ( keys %{$hashref} ) {
   print $_ . " contains " . scalar(%{$hashref->{$_}) . " keys.\n";
}

keys returns a scalar of keys, which you can count with scalar. :-) edit: put a pretty space before keys :-)

[AnomalousMonk]

>perl -wMstrict -le
"my $hashref = {
   first  => { foo => 'bar', bar => 'baz', flop => 'floodle' },
   second => { bar => 'foo', baz => 'bar', etc  => 'plodle'  },
   };
 foreach ( keys %{$hashref} ) {
   print qq{$_ contains } . scalar(%{$hashref->{$_}}) . qq{ keys.};
   }
"
first contains 3/8 keys.
second contains 3/8 keys.

Please note:
• proper string definitions of values of hashes;
•  scalar(%{$hashref->{$_}}) vice  scalar(%{$hashref->{$_});
• per Re^2: num keys of the hash within hash?, the stringization of a hash does not necessarily imply the number of keys of the hash.