Re^2: Mini-Tutorial: Scalar vs List Assignment Operator

[ikegami]

Thanks. Fixed.

Yes, there's nothing special about lvalue subs. f() doesn't cause the list assignment operator to be used, but (f()) does.

$ perl -wle'sub f :lvalue { $x,$y } f()=(4,5); print $x,$y'
Useless use of a constant in void context at -e line 1.
Use of uninitialized value in print at -e line 1.
5

$ perl -wle'sub f :lvalue { $x,$y } (f())=(4,5); print $x,$y'
45