Apparently not. I thought you just misread. Are you saying you were deliberately misquoting?
If you're playing games, they're going over my head.
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Are you being dense on purpose??
Commutativity Breakage != Commutative Breakage
(which would be the answer to your question #1)
Commutativity Breakage == Breakage of the Commutativity
i. e., the commutativity (Of the ~~ operator) is broken, or IOW, is not working anymore.
And, because the commutativity is not working anymore, code references are no longer treated specially. (They were treated specially before, because the ~~ operator was commutative). Easier to parse now?
[]s, HTH, Massa (κς,πμ,πλ)
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