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Re^7: Perl 5.11.0 now available

by BrowserUk (Patriarch)
on Oct 04, 2009 at 03:18 UTC ( [id://799073]=note: print w/replies, xml ) Need Help??


in reply to Re^6: Perl 5.11.0 now available
in thread Perl 5.11.0 now available

In short, broken commutativity != commutatively broken

Ah! So you can infer my meaning...


Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.

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Re^8: Perl 5.11.0 now available
by ikegami (Patriarch) on Oct 04, 2009 at 04:24 UTC

    Apparently not. I thought you just misread. Are you saying you were deliberately misquoting?

    If you're playing games, they're going over my head.

      Due to the commutativity breakage, code references are no longer treated specially when appearing on the left of the ~~ operator,

      Re-read that original in the light of your new insight and ask yourself:

      1. Is the breakage, commutative?
      2. Are code references no longer treated specially because the breakage is commutative?

      Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
      "Science is about questioning the status quo. Questioning authority".
      In the absence of evidence, opinion is indistinguishable from prejudice.

        No to both. Nothing is said about the breakage. It is not said to be commutative.

        What new insight? I've been saying the same thing since my first post.

        Are you being dense on purpose??
        Commutativity Breakage != Commutative Breakage
        (which would be the answer to your question #1)
        Commutativity Breakage == Breakage of the Commutativity
        i. e., the commutativity (Of the ~~ operator) is broken, or IOW, is not working anymore. And, because the commutativity is not working anymore, code references are no longer treated specially. (They were treated specially before, because the ~~ operator was commutative). Easier to parse now?
        []s, HTH, Massa (κς,πμ,πλ)

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