Re: Regex for matching n-fold repititions of arbitrary characters

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Re^2: Regex for matching n-fold repititions of arbitrary characters by pat_mc (Pilgrim) on Oct 08, 2009 at 19:15 UTC
Thanks, ikegami ... I knew there should be an easy way to do it ... but had not used backreferences in regexes before. One follow-up to your post: Is the `s` modifier really required? Thanks again! Pat	[reply] [d/l]
Re^3: Regex for matching n-fold repititions of arbitrary characters by ikegami (Patriarch) on Oct 08, 2009 at 19:17 UTC
Depends on what you want /`.`/ to match. If you want to match repetitions of any character, yes. If you want to match repetitions of specific characters, no, since you won't be using /`.`/.	[reply] [d/l] [select]
Re^4: Regex for matching n-fold repititions of arbitrary characters by pat_mc (Pilgrim) on Oct 08, 2009 at 19:49 UTC
Hm ... I follow you so far, ikegami ... but why do I get different output in the following two cases: `~$ perl -le 'print $& if "aabbaab" =~ /aa\|bb/g' ~$ perl -le 'print join "\n", ( "aabbaab" =~ /aa\|bb/g )' aa bb aa ~$ perl -le 'print join "\n", ( "aabbaab" =~ /(.)\1/g )' a b a` [download] The first two system responses are clear ... but why does the last regex using backreferences return only single characters?	[reply] [d/l]
Re^5: Regex for matching n-fold repititions of arbitrary characters by ikegami (Patriarch) on Oct 08, 2009 at 21:17 UTC
Re^6: Regex for matching n-fold repititions of arbitrary characters by LanX (Saint) on Oct 08, 2009 at 21:39 UTC
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Re^5: Regex for matching n-fold repititions of arbitrary characters by bv (Friar) on Oct 08, 2009 at 20:21 UTC
Re^5: Regex for matching n-fold repititions of arbitrary characters by LanX (Saint) on Oct 08, 2009 at 21:28 UTC


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