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Re: does split(".") work?

by Joost (Canon)
on Nov 15, 2009 at 23:23 UTC ( #807329=note: print w/replies, xml ) Need Help??

in reply to does split(".") work?

split does not split on a string but on a regular expression. Dot "." is the "match-all" character in a regex so your split won't return anything.

You want my @values = split /\./, $ip instead.

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Re^2: does split(".") work?
by jwkrahn (Monsignor) on Nov 16, 2009 at 00:23 UTC
    Dot "." is the "match-all" character in a regex so your split won't return anything.

    Actually split returns a lot of things, it's just that the way list assignment works there is nothing left to put in the array.    If you make a slight change you can see everything that split returns:

    $ perl -le'my $ip=""; my @values = split(".", $ip, -1); pr +int $ip,"\t\t",$#values,"\n";' 12
      Not sure what you mean about list assignment; the difference is that a third parameter of -1 makes split keep trailing empty strings where by default it discards them. In your example, split returns 13 empty strings (one from before the first character of $ip, one for each position between characters, and one from after the last character.)
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