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Re^3: accessing the result of a match as an array

by JadeNB (Chaplain)
on Dec 24, 2009 at 23:04 UTC ( #814304=note: print w/replies, xml ) Need Help??


in reply to Re^2: accessing the result of a match as an array
in thread accessing the result of a match as an array

What's the advantage of your latter snippet over

perl -e '"hello awesome" =~ /(el).*(om)/ and print $2;'
or, if you don't like to count,
perl -e '"hello awesome" =~ /(el).*(om)/ and print $^N;'

By the way, while I'm nattering about linking, [doc://perlvar#%-] (but not [doc://perlvar#%25-], which over-escapes) facilitates the OP's laziness: % .

UPDATE: It seems to me that the link text for [doc://perlvar#%-] should be '%-', but it's actually '% '. Is this a bug? (Oops, that's right: - is parsed as a word separator, as in [doc://perlrun#Location-of-Perl].)

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Re^4: accessing the result of a match as an array
by AnomalousMonk (Bishop) on Dec 24, 2009 at 23:21 UTC
    What's the advantage of your latter snippet ...

    None. In the context of the OP, it's essentially a Stupid Regex Trick. But then, in the same context
        pop @{[ whatever ]}
    is essentially a stupid array dereference trick.

    Update: ikegami nailed the reason why.

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