http://www.perlmonks.org?node_id=837448


in reply to Top and bottom 10 percent elements of an array

This works better for the given elements. It gives the result as you need. Refer splice to know about it.

my @array = (2 ,4, 3, 8, 9, 12, 13, 20, 18, 7 ); my $percent = (scalar @array * 0.20); my (@resultA, @resultB); my @ordered = sort {$a <=> $b} @array; @resultB = splice(@ordered, 0, $percent); @resultA = splice(@ordered, (scalar @ordered - $percent)); print "@array", "\n"; for (my $i=0; $i < scalar @array; $i++) { if ( grep { $array[$i] eq $_ } @resultA ) { $array[$i] = 'A'; } elsif ( grep { $array[$i] eq $_ } @resultB ) { $array[$i] = 'B'; } else { $array[$i] = '-'; } } print "@array", "\n";

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Re^2: Top and bottom 10 percent elements of an array
by sesemin (Beadle) on Apr 29, 2010 at 05:31 UTC
    Thanks, easy to implement and easy to understand.