|
|
|
| We don't bite newbies here... much | |
| PerlMonks |
Re^3: Finding all divisors of an integerby Anonymous Monk |
| on Jul 21, 2010 at 23:06 UTC ( [id://850738]=note: print w/replies, xml ) | Need Help?? |
|
If you multiply all the possible combinations of the prime factors together (and get rid of repeats), you get a list of all the factors, and the number itself.
I wonder how you multiply all the possible combinations of a list...
In Section
Seekers of Perl Wisdom
|
|
||||||||||||||||||||||