Sum of Input

[changma_ha]

hi all. I am trying to do a program in which the user give some numbers as input and the output is the sum of the numbers in that input. I am getting the sum right but the problem is when i am giving input after it . it takes the output of the fist input as it input.my code is like:

#! /usr/bin/perl
use strict;
use warnings;
#use Data::Dumper;

my $linetotal=0;
my $gtotal =0;
my $n =0;

while (my $line = <STDIN>){
    #$line =~ s/^\s+|\s+\n$/ /g;
    #chomp ($line);
    my @numbers = split (/ /,$line);
        $n++;
     #print Dumper \@numbers;
    foreach my $number (@numbers){
        $linetotal +=$number ;
        #chomp ($linetotal);
        
               
        
    }
#    $line =<STDIN>;
 print "Total in $n input is : $linetotal \n";    
    
       
}
$gtotal +=$linetotal;
    print "Grand Total is : $gtotal\n";

Suppose if i give input as

1 2 3

it should give output as

"Total in 1 input is 6"

2 4 5

Total in 2 input is 11

Instead it is giving the 2nd output as 17. plz help me out.Thanks in advance.

[marto]

This isn't your fist post here, this is in the wrong section of the forum. Where should I post X? is displayed each time your are posting, please don't ignore it's advice.

Examine your code and the input data (note that 6 + 11 = 17), notice that you aren't resetting $linetotal to zero after printing the results for each line.

[changma_ha]

Thanx marto for your suggestion and advice.From now onwards i will not post in the wrongs threads. Now my problem is solved.

[SuicideJunkie]

To solve your problem next time, add lots of print statements.

In this case, extra print statements could have shown you:

Summing over 3 numbers; 1 2 3
Adding 1 Total is 1
Adding 2 Total is 3
Adding 3 Total is 6
Summing over 3 numbers; 2 4 5
Adding 2 Total is 8
Adding 4 Total is 12
Adding 5 Total is 17

If you had seen that, the bug would be obvious, right? :)

[murugu]

You need to reset the $linetotal at the end of the loop.

[tilly]

And increment $gtotal inside the loop.