Re: Pre vs Post Incrementing variables

[repellent]

The docs mention no guarantees for the result of such code. Here's what it seems to be doing (at this time of writing):

• ++$i increments $i and then returns an alias to $i
• $i++ returns a copy of $i and then increments $i

(++$i, ++$i) returns two aliases to $i, which has been incremented twice, resulting in (2, 2).

($i++, $i++) returns two copies of $i, one before and one after the first post-increment, resulting in (0, 1).