in reply to 0 illegal modulus?
Well, had I designed the Perl interpreter (*chuckle*), I'd've made sure that mod 0 was illegal for consistancy with the assembly language on most (that I've dealt with) platforms. For instance, on the x86, the modulus is calculated by doing and I?DIV instruction, which leaves the remainder of the division (the modulus) in the appropriately sized register (AH, DX, or EDX). The brief upshot of this is that, since the modulus is actually calculated with a division, modulus 0 would give you a divide by 0 error. More of an explanation than a solution, really.
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