Re^2: NaNs are true (NaN == 0 -> true? Really?)

[BrowserUk]

That's all very logical, except that at the end you seem to have arrived at the situation where you would have an implicit test of a NaN against zero be true?

NaN == 0 -> true cannot be right.

[pajout]

What about idea that NaN never matches numerical comparison?


NaN == 0 #false
NaN != 0 #false
NaN == NaN #false
NaN != NaN #false

[BrowserUk]

I think all of those are correct, though not particularly useful. They should also prompt (at least) a warning, though I think a catchable exception is better.

You also have to be careful to distinguish between a variable containing NaN, and a constant NaN I think.

That is, I think the only time any comparison involving a variable containg NaN should result in a true value, is if it is compared against a predefined constant NaN; were one to be provided. Though an isNaN( $x ) function or equivalenly $x->isNan() method would serve the same purpose and be less likely to confuse.