Re^4: How to process multiple input files?

[John M. Dlugosz]

No, it tests for normal Truth. An undef, an empty string, a "0" etc. will all test as False after being assigned to $line.

[Anonymous Monk]

Check your answers, its easy :)

$ perl -le " while ( my $line = <> ) { 1 } print $. "
0
0
0
0
^Z
4

$ perl -MO=Deparse -le " while ( my $line = <> ) { 1 } print $. "
BEGIN { $/ = "\n"; $\ = "\n"; }
while (defined(my $line = <ARGV>)) {
    do {
        '???'
    };
}
print $.;
-e syntax OK

[John M. Dlugosz]

It's not a problem with normal line-oriented use because the \n character is present on the end of every line with the possible exception of the last which then won't be empty. You got "0\n" in the string, not an empty string, not "0" alone.

Try something like: while ( my $line = <> ) { say !!($line) } print $. and you'll see that each read is True as well as being defined.

Recall as I explained originally, I'm concerned with totally empty files causing an empty string and testing false, or (less likely because it doesn't look like an xml file) a file containing a 0 only and no terminating end-of-line.

However, I do stand corrected, after checking the perl IO reference: I was thinking that the special meaning of Truth applied only to implicit assignment to $_ in the condition. However, the 5.14 docs does indeed say "the assigned value (whether assignment is automatic or explicit) is then tested to see whether it is defined...".

[Anonymous Monk]

It's not a problem with normal line-oriented use because the \n character is present on the end of every line with the possible exception of the last which then won't be empty. .... Try something like

Its not a problem at all as B::Deparse shows. The idea was for you to try it

$ perl -lE " open ARGV, q[<], \qq[0$/0$/0]; while ( my $line = <> ) { 
+say q[!!],!!($line) } say $. "
!!1
!!1
!!
3

or

$ perl -e " print qq[0\n0\n0] " > 3zeros

$ od -tacx1 3zeros
0000000   0  cr  nl   0  cr  nl   0
          0  \r  \n   0  \r  \n   0
        30 0d 0a 30 0d 0a 30
0000007

$ perl -le " while ( my $line = <> ) { 1 } print $. " 3zeros
3

$ perl -E " while ( my $line = <> ) {  say q[!!],!!($line) } say $. " 
+3zeros
!!1
!!1
!!
3