Re: japhy's Perl Film picks (some are puzzles...)

[petdance]

Some of those are completely brilliant, but I really think that

pop @mohicans;

is more accurately

$mohicans[-1];

Also, I think that the data structure for

@couples = map [ pop @brides, pop @brothers ], 1..7;

should really be

%couples = map { (pop @brothers, pop @brides) }, 1..7;

Note the hash as having a "has-a" relationship, right?

xoxo,
Andy
--
I was dreaming when I wrote this, so sue me if I go too fast.

[japhy]

Technically, if all the mohicans died, it'd be $mohicans[0] as well, no? ;)

japhy -- Perl and Regex Hacker

[dga]

Or to get the overall effect.

$last = map { pop @mohicans } @mohicans;

Thus leaving no mohicans other than the one you have in $last.