Re: (tye)Re: Unusual Closure Behaviour

[suaveant]

his first example

{ 
  my $x;
  sub foo {
     return ++$x;
  }
}

is very much a closure, because $x is lexically scoped to that block, and sub foo is by definition global and survives the loop, $x goes away, except for the one reference in sub foo. his second one, however, would not be a closure.

                - Ant