Appending two files

[abcdefg]

I am trying to append two files in a single file using command line arguments but I am getting many errors like Global symbol "$usage" requires explicit package name at add.pl line 14. Global symbol "$usage" requires explicit package name at add.pl line 26. Global symbol "$result" requires explicit package name at add.pl line 32.

#!/usr/bin/perl
use strict;
use warnings;
use File::Basename;
$| = 1;

my $scriptname  = fileparse(__FILE__);
my $t;
my $imgfile;
my $hash_filename;
my $Signed_filename

my $usage       = " 
Usage: $scriptname (-i <file1> -t <file2> -o <Output_file>  ) 

       ** Image Types **
       -i <file1>        : Required:
       -t <file2>  : Required.Inout file to read the unsigned file
       -o <Output_file>       : Required. Output file to write the sig
+ned input file         
              
          
";
if ($#ARGV == -1) # if user enters no arguments, exit with the usage i
+nstructions
{
    die $usage;
}
# Get the command line options passed to us
$result = GetOptions ("File1=s"   => \$file1,
                      "File2=s"   => \$file2,  
                      "out=s"   => \$Output_file);
                      
open(FH,">$Output_file") or die "$!\n";
print FH $file1,"\n" ;
print FH $file2,"\n" ;
close FH;

What am I doing wrong?

[CountZero]

You forgot to end line 12 with a semi-colon.

[Anonymous Monk]

What am I doing wrong?

Well, you're attempting to use "$scriptname" as if it is a defined variable, but it is not, you've never defined it. You're using warnings without understanding why/how to use them, in short, you should Read this if you want to cut your development time in half!

[Marshall]

Well, the messages pretty much speak for themselves. $scriptname is used in your $usage variable, but never declared. Nowhere do you use the value of $result that you get from GetOptions. I would also go ahead and "use strict;".

[ww]

It's no part of your code mistakes... but your language needs correction (or, "invited pedantry" if you don't care about being clear and accurate).

You're trying to 'concatenate' two files; not "append" them. You might append a second file to the first (result: two files, the first of which contains the original contents of both), but what you're trying to do is create a third file from the first two.