in reply to listing all subdirectories of directory into file
If you're familiar with Path::Class, I recommend for you to use Path::Class::Dir->recurse().
Create a Path::Class::Dir object as follows:
Once you create the object, use recurse() method:use Path::Class qw/dir/; my $dir = dir( 'basedir' ); # platform-neutral syntax
recurse() is similar to File::Find module. If you use recurse(), you can handle Path::Class::File objects in the callback subroutine.my @plain_files; $dir->recurse(callback => sub { my $file = shift; # Path::Class object return if $file->is_dir; push @plain_files, $file; });
UPDATE: Corrected my typo ( recruse -> recurse ). Thanks to jdrago999. In addition, I noticed $file may be a Path::Class::Dir object, and so simplified my comment in the code example ( "Path::Class::File object" -> "Path::Class object" ).
|
---|
Replies are listed 'Best First'. | |
---|---|
Re^2: listing all subdirectories of directory into file
by jdrago999 (Pilgrim) on Jun 08, 2012 at 17:20 UTC |
In Section
Seekers of Perl Wisdom