if statement confusion

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hi, I was using the short c-style IF statment in my code and I understood it worked by EXPR ? TRUE :FALSE; however when I compiled this:

6 < 8 ? $ans = "true" : $ans = "false";

$ans was false... can anyone explain what happened?

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Re: if statement confusion by toolic (Bishop) on Jun 11, 2012 at 14:15 UTC
B::Deparse (Tip # 6 from Basic debugging checklist) `perl -MO=Deparse -e '6 < 8 ? $ans = "true" : $ans = "false";' ($ans = 'true') = 'false';` [download] Try: `$ans = 6 < 8 ? "true" : "false";` [download] Conditional Operator	[reply] [d/l] [select]
Re: if statement confusion by Anonymous Monk on Jun 11, 2012 at 14:13 UTC
Operator precedence. What you got was: `(6 < 8 ? $ans = "true" : $ans) = "false";`	[reply] [d/l]
Re: if statement confusion by davido (Cardinal) on Jun 11, 2012 at 17:31 UTC
Write it like this: `$ans = 6 < 8 ? 'true' : 'false';` [download] update: Aack! I didn't notice that toolic had already given this suggestion. Sorry for creating an echo in the Monastery. :) Dave	[reply] [d/l]
Re: if statement confusion by Anonymous Monk on Jun 11, 2012 at 14:56 UTC
Thank you :)	[reply]
Re: if statement confusion by eyepopslikeamosquito (Archbishop) on Jun 12, 2012 at 12:28 UTC
See also: Surprised by Perl parse of ternary operator.	[reply]
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