|Just another Perl shrine|
Re: difference between ($scalar) and $scalarby tadman (Prior)
|on Jul 21, 2001 at 11:03 UTC||Need Help??|
The difference is that one can possibly land you in jail, while the other won't. Or something to that effect.
I'm a particular fan of brackets, even when not strictly necessary, but I have been warned that this does have some side-effects on commands that are sensitive to the calling context. Maybe your biggest fear is only the Perl Police.
Certain commmands do different things in different contexts. Consider an example from the above article:
my ($fortune) = `fortune`;When the backtick detects "array context", it splits up the lines returned by the command into an array and returns it. $fortune then gets the first element/line and the rest go unassigned.
my $fortune = `fortune`;In scalar context, the entire result is returned in one string, meaning that the linefeeds are not split.
Or compare the two here, using the context sensitive localtime function:
This prints, for me at least: "42 / Sat Jul 21 03:02:42 2001", which shows you how important those brackets can be.