TL;dr
but that's really what you want or just a C&P disaster? ;)
'b' => exists($tests{'b'}) && defined($m=$tests{'b'}) ? $m : 0,
'a' => exists($tests{'b'}) && defined($m=$tests{'a'}) ? $m : 0,
^^^^^
update
OK now I looked closer, I think you get bitten by passing the same lvalue $m twice in the same statement.
update
yep, seems I'm right, if you force Perl to pass an immutable copy instead of the var it works like expected
use strict;
use warnings;
use Data::Dump qw/pp dd/;
my %tests = (
'a' => 10,
'b' => 20,
);
my $m;
# this seems to assign $m once and never bother to check again
my %hash;
%hash =
(
'b' => exists($tests{'b'}) && defined($m=$tests{'b'}) ? $m : 0,
'a' => exists($tests{'b'}) && defined($m=$tests{'a'}) ? $m : 0,
);
pp \%hash;
%hash =
(
'b' => exists($tests{'b'}) && defined($m=$tests{'b'}) ? (0+$m) : 0,
'a' => exists($tests{'b'}) && defined($m=$tests{'a'}) ? (0+$m) : 0,
);
pp \%hash;
%hash =
(
'b' => exists($tests{'b'}) && defined($m=$tests{'b'}) ? "$m" : 0,
'a' => exists($tests{'b'}) && defined($m=$tests{'a'}) ? "$m" : 0,
);
pp \%hash;
{ a => 10, b => 10 }
{ a => 10, b => 20 }
{ a => 10, b => 20 }
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