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<Updated>
I like nuance's idea (above). I now store undef as the value when a key is missing from one hash. See nuance's description above for an explanation of the "return" values.
</Updated>

Here's some punctuation for you:

(This is a short, concentrated way to do it - only 4 lines)

# Keys 7 and 8 are unique, keys 2,4 and 6 have different values my %R = (1=>1, 2=>2, 3=>3, 4=>4, 5=>5, 6=>6, 7=>7); my %S = (1=>1, 2=>'b', 3=>3, 4=>'d', 5=>5, 6=>'f', 8=>8); # 1) Keys in %R which are not in %S # 2) Keys in %S which are not in %R # 3) Keys in both which have different values my %Diffs = ((map(($_ => [$R{$_}, undef]), grep {not exists $S{$_}} k +eys %R)), (map(($_ => [undef, $S{$_}]), grep {not exists $R{$_}} k +eys %S)), (map(($_ => [$R{$_}, $S{$_}]), grep {exists $S{$_} and $R{$_} ne $S{$_}} keys %R)) +); # Print out what we found for (sort keys %Diffs){ print $_, ': ', join(', ', map(defined $_ ? $_ : 'undef', @{$Diffs{$ +_}})), "\n"; }
A couple points to note:
  • if your values are numeric, change the 'ne' in the third Diffs section
  • we use an anonymous array ref to store the values in %Diffs, so remember to dereference it when you use %Diffs

Enjoy!

Russ


In reply to Re: diff of two hashes. by Russ
in thread diff of two hashes. by ChuckularOne

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