I was wondering about the efficiency of this solution so I compared it with GrandFather's solution:
# x.pl
use Benchmark qw(timethese cmpthese);
cmpthese(
-2,
{
GrandFather => sub {
my $idxMax = 0;
$ARGV[$idxMax] > $ARGV[$_] or $idxMax = $_ for 1 .. $#ARGV
+;
$idxMax;
},
reisinge => sub {
[ sort { $ARGV[$b] <=> $ARGV[$a] } 0..$#ARGV ]->[0];
}
}
);
These are the results of the benchmarking:
$ perl x.pl $(seq 1 1000)
Rate reisinge GrandFather
reisinge 3742/s -- -3%
GrandFather 3864/s 3% --
$ perl x.pl $(seq 1 10000)
Rate reisinge GrandFather
reisinge 377/s -- -5%
GrandFather 395/s 5% --
$ perl x.pl $(seq 1 100000)
Rate reisinge GrandFather
reisinge 34.1/s -- -18%
GrandFather 41.6/s 22% --
GrandFathers's solution seems to be more efficient, i.e. it's faster (to run) and scales better. But mine is shorter :-).
It all comes to this: the simplest way to be happy is to do good. -- Helen Keller
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