comment on

s/\b($old)\b/lc$new^$1^lc$1/gie

Update:
In case $new=~/\W/ or length$new<length$old it may be slightly more complicated:
s/\b($old)\b/lc$new^($1^lc$1)&(lc$new^uc$new)/gie

In reply to Re: Case-preserving substitutions by I0
in thread Case-preserving substitutions by wasii

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