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Do you know where your variables are?

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I see your motivation, and I get the train of thought that led to your initial assumption -- a hash element is an lvalue, and there's an intuitive sense that a loop variable is being used as an lvalue -- elements of the list are being assigned to it on each iteration.

But that intuitive sense seems to be wrong in a subtle way. Many of us have relied on the documented behavior that results in things like:

my @array = qw/1 2 3 4/; foreach my $elem ( @array ) { $elem *= 5; } print join " ",@array,$/; __OUTPUT__ 5 10 15 20
As pointed out by "perldoc perlsyn": 'the "foreach" loop index variable is an implicit alias for each item in the list that you're looping over.' Another passage from perlsyn, very close afterwards, points out: '"foreach" probably won't do what you expect if VAR is a tied or other special variable. Don't do that...'

Next, we'd have to look closely at how perl stores variables internally (The Damian's excellent book "Object Oriented Perl" has one of the nicest explanations), and try to work out how different a hash element is from a normal scalar. Well, it's late, and I won't try that just now... The point is that the loop variable is not being used as an lvalue -- it's something else with special properties.

update: Regarding perl implementation issues, I would suppose that the compiler has a very rigid sense of for-loop syntax: the thing after "for" (or "foreach") must be a scalar; if there's a curly brace after that, it probably interprets this as the start of a block (not a hash index), and reports the syntax error because there's no list being provided for the iteration. Of course, the error is reported if you're using an array element (square-brackets) as well.

In reply to Re: Surpised by foreach iterator limitation by graff
in thread Surpised by foreach iterator limitation by shotgunefx

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