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I found 301 years with a unique solution in the range 2000 till 3000. I used a different, IMO, simpler program than the one you describe. I think you are referring to 2001 and 2005 as candidates in the counter puzzle.

Anyway, my program is after the readmore tag.

Abigail

#!/usr/bin/perl use strict; use warnings; my $from = 2000; my $till = 3000; my @nums; for my $x (0 .. 9) { for my $y ($x .. 9) { for my $z ($y .. 9) { my %seen; push @nums => [grep {!$seen {$_} ++} map {s/^0{1,2}//; $_} "$x$y$z", "$x$z$y", +"$y$x$z", "$y$z$x", "$z$x$y", +"$z$y$x"] } } } sub all_sub_sets; sub all_sub_sets { return unless @_; my $f = shift; my @r = all_sub_sets @_; @r => [$f] => map {[$f => @$_]} @r } my %answers; foreach my $num (@nums) { my @sets = all_sub_sets @$num; foreach my $set (@sets) { local $" = " + "; my $sum = eval "@$set"; if ($sum >= $from && $sum < $till) { push @{$answers {$sum}} => $set; } } } for my $sum ($from .. $till - 1) { local $" = " + "; print "$sum = @{$answers{$sum}[0]}\n" if $answers {$sum} && 1 == @{$answers {$sum}}; }

In reply to Re: Coming soon: Algorithm::Loops by Abigail-II
in thread Coming soon: Algorithm::Loops by tye

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