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The stupid question is the question not asked

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it seems to me specifically to be saying that you can't use a variable there.

Then why did the OP say "Can't use a \x variable" instead of "can't use a variable"?

If I say "The Western sky is orange", doesn't that tell you something about the Eastern sky? At the very least, I'm leaving the possibility of the Eastern sky being a different colour. In fact, it's quite likely it's either a different colour or I don't know it's colour.

capture buffers (which I guess means $1 instead of \1?)

I mean "what is captured". Technically, they exist as a reference to the string being matched, a start position and an end position (or something similar).

$1 and \1 are both windows into them, and so are @-, @+, %-,%+ and $^N.

since their values don't change during the regex match

They're not used at all during regex matching. There isn't even a regex opcode to refer to them. The only way they can be accessed is via \1 (etc) and via Perl code blocks ((?{ }) and (??{ }). Neither of those can be used in a quantifier.

And if they don't change — if you can't even give them a value — how can you consider them variables?

In reply to Re^7: Regex fun by ikegami
in thread Regex fun by Hena

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