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I'm not sure that's what the original poster needs. chr(0xD6D0) means Unicode code point U+D6D0 which is the character '훐'. Whereas the poster said the bytes represented by the ASCII string 'D6D0' are the character '中' in a 'GB' encoding. I'm not very knowledgeable about Asian encodings but I'll assume that the specific encoding is GB-2312.

So the things we need to do are:

  1. convert the ASCII hex string into bytes
  2. decode the bytes from GB-2312 to Perl's internal character representation
  3. convert to a suitable output encoding

Here's a complete script which does all of that:

#!/usr/bin/perl use strict; use warnings; use Encode qw(decode); my $ascii_hex = 'D6D0'; # continue for as many bytes as required my $bytes = pack('H*', $ascii_hex); my $character_string = decode('gb2312', $bytes); binmode(STDOUT, ':utf8'); print $character_string, "\n";

In reply to Re^2: How do I convert a sequence of hexes (D0 D6) to Chinese characters (中)? by grantm
in thread How do I convert a sequence of hexes (D0 D6) to Chinese characters (中)? by dstrom

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