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in reply to Re^8: perl 5.12 BSD portability (CPAN test result)...print
in thread perl 5.12 BSD portability (CPAN test result)...print

Without an explicit filehandle, where does the output of print $x go? How is Perl to tell the difference between "print the contents of $_ to the filehandle in $x" from "print the contents of $x to the currently selected filehandle"?

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Re^10: perl 5.12 BSD portability (CPAN test result)...print
by perl-diddler (Chaplain) on Mar 20, 2013 at 03:15 UTC
    You mean like this:
    perl -e 'use P; my $x=27; P $x; my $y=\*STDOUT; P $y,"through STDOUT=%s", $x' 27 through STDOUT=27
    What it can't easily do is, both:
    P $x #and P STDOUT $x #without the comma
    where $x is not an object. That takes "special parsing"...but if the right prototype element was created to do that.. if not an object, then pass as a scalar), that would work too. I.e. I can get the 2nd case to work, but then the 1st case doesn't.

    So is the only reason print has to be an operator is to handle printing to a <FH> w/o the comma, since the first case -- telling the difference between "$X" as a var and $x as a FH is fairly straightforward.

    Note -- if you really wanted to print FROM file handle "$x", I'd have to add code for that...but if the file is open for READ/WRITE -- no way to tell.

    FWIW, P does print from File handles (but not as the first arg or w/o a format statement). It reads the file handle and prints the contents as part of the output:

    # perl -e 'use P; P \*STDOUT, "Input was: %s", \*STDIN; ' my input Input was: <*=my input >