- #1

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**how much force is needed....**

## Homework Statement

How much force is needed to push a 500N block of ice 6m up a 3m incline. and neglect friction

## Homework Equations

work =fd

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- Thread starter polishguy1234
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- #1

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How much force is needed to push a 500N block of ice 6m up a 3m incline. and neglect friction

work =fd

- #2

LowlyPion

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## Homework Statement

How much force is needed to push a 500N block of ice 6m up a 3m incline. and neglect friction

## Homework Equations

work =fd

## The Attempt at a Solution

Welcome to PF.

Any ideas on how you can push something 6m up a 3m incline?

- #3

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thanks. and no i dont know how to do this. Im trying to learn though.

- #4

LowlyPion

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So is 3m the height of the incline? And 6m the distance of the incline?

- #5

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Yeah

- #6

LowlyPion

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So what is that angle?

Knowing the angle then you can determine the force against gravity needed to push the block can't you?

- #7

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If you use the formula W=fd:

500N(weight of an object can also be considered the force) X 6m ( the distance) = 3000 J

I hope this helped

- #8

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Be careful Jenn and make a diagram of this situation. The object is moving 6m but does it take 500N or a force equal to the weight to move it the 6 m?

The problem appears to indicate that the path of the mass is 6m and the vertical height is 3m. It's not clear. That, along with the weight of the object is adequate to calculate the force needed to move it up the ramp.

- #9

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Well 3 m height and 6m distance would be like a road inclination of 50%(per cent, not really percentage but per cent as in hundred) or 50 m height gain every 100m distance.

So 50% inclination would resemble like 26.57 degree according to the Grade (slope) page on wikipedia.

So now you know 6 m distance, 3 m height with a 26.57 degree inclination.

- #10

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Conservative force of gravity.

For conservative force, the work is the same along all paths joining two given points.

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