in reply to (jeffa) Re: A better mod (%) operator?
in thread A better mod (%) operator?
The problem with overload though, is that you cannot define some new token such as /% - you have to use an existing one.perl 6 solves this problem. something like:
i'll be glad i can finally add the ,= operator i've been looking for to replace push.my sub operator:%/ is prec(\&operator:%) ($x, $y) { ... }
~Particle *accelerates*
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Re: Re^2: A better mod (%) operator?
by Kickstart (Pilgrim) on Jul 10, 2002 at 21:46 UTC |
In Section
Meditations