in reply to Confused by Perl ternary operator
Operator Precedence, again.
A ? B = C : D = E # resolves ( A ? ( B = C ) : D ) = E
So, no matter what A evaluates to, E is being assigned, either to "B = C" (which is the same as assigning to B) or D. In your case B and D are identical, so your ?: operator doesn't do anything useful. Solution:
@_ ? ( $param2 = shift ) : ( $param2 = "Shift" ); # and while we're at it, of course, refactor that $param2 = @_ ? shift : "Shift"
The last line demonstrates why the precedence of "?:" vs. "=" is actually sensible. HTH