in reply to Finding the max()/min()
Here's an interesting one that doesn involve a comparison operator (even an obfuscated one):
The math behind that is: take the average of the two numbers, and then add half their difference (start halfway between, and then go up by half). So: (x+y)/2 + abs(xy)/2, and then factor out the division by two.($x + $y + abs($x  $y)) / 2
 :Wq Not an editor command: Wq


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Re: Finding the max()/min()
by benizi (Hermit) on Nov 12, 2004 at 21:58 UTC  
by etcshadow (Priest) on Nov 12, 2004 at 22:12 UTC 
In Section
Meditations