http://www.perlmonks.org?node_id=879570


in reply to Re^3: xml simple not a hash reference
in thread xml simple not a hash reference

Thanks, I am almost there. I am using the following code:

my $type = ref( $e->{mealplans}->{mealplan} );

if ($type eq "ARRAY")
{

$mealplans=$e->{mealtypes}->{mealtype};

    for my $mealtype ( @{$e->{mealtypes}->{mealtype}} ) {
        $rateid = $mealtype->{rateid};
        
        print "$mealtype";
    }
}

[download]

It prints out: HASH(0x27acfbc)HASH(0x27acfcc) How do I get the Array readable?

Replies are listed 'Best First'.
Re^5: xml simple not a hash reference
by morgon (Priest) on Dec 29, 2010 at 07:51 UTC
    It prints out: HASH(0x27acfbc)
    This indicates that your $mealtype variable does not hold a scalar or array, but a reference to a hash.

    The easiest way to print that is probably to use Data::Dumper: 

    use Data::Dumper;
print Dumper($mealtype);

    [download]
[reply]
[d/l]
      To quote perldata
      Perl has three built-in data types: scalars, arrays of scalars, and associative arrays of scalars, known as "hashes". A scalar is a single string (of any size, limited only by the available memory), number, or a reference to something (which will be discussed in perlref).
[reply]

In Section Seekers of Perl Wisdom